Comment compter les votes à partir de la liste et stocker dans un dictionnaire pour suivre le nombre de votes

Si les votes ont toujours la même structure x voted y , vous pouvez faire:

# get a defaultdict for storing the result
from collections import defaultdict
result = defaultdict(int)

# split out the voted from each string in the list
pairs = [i.split(' voted ') for i in list]

# for each pair, increase the value for that key in the defaultdict by 1
for _, vote in pairs:
    result[vote] += 1

# convert back to dict
result = dict(result)

from collections import defaultdict

mylist = ["a voted b", "c voted b", "d voted e", "e voted skip"]

votes = defaultdict(int)
for item in mylist:
    votes[item.split()[-1]] += 1

Qu'en est-il d'un one liner:

from collections import Counter
result = dict(Counter([s.split(' voted ')[-1] for s in list]))

Je considère que la liste utilise le format suivant x voted y qui change x et y. Aussi, j'ai décidé de ne pas utiliser de bibliothèque externe

Voici une fonction de mon code

def count(list):
    # Simplifying the list with the format 'x voted y' to a list with the format 'y'
    votes = [vote.split(' voted ')[1] for vote in list]
    result = {}
    for vote in votes:
        if vote in result.keys():
            result[vote] = result[vote] + 1
        else:
            result[vote] = 1
  

l = ["a voted b", "c voted b", "d voted e", "e voted skip"]
v = {}
for i in l:
    vs = i.split(' ')
    if vs[2] not in v:
        v[vs[2]] = 1
        continue
    v[vs[2]] += 1

La manière la plus propre pourrait être d'utiliser des pandas :

{'b': 2, 'skip': 1, 'e': 1}

résulte en:

lst = ["a voted b", "c voted b", "d voted e", "e voted skip"]
pd.Series([i.split('voted')[1].strip() for i in lst]).value_counts().to_dict()