Comment vérifier si une liste contient 2 éléments d'une autre liste?

Vous pourriez écrire une fonction pour vérifier les éléments en commun entre les deux listes, et après vérifier si la quantité de ces éléments est égale à 2.

Par exemple:

def intersection(list1, list2): 
     lst3 = [value for value in list1 if value in list2] 
     return lst3 


list1 = ["a", "b", "c"]
list2 = ["a", "f", "g", "b"]

if len(intersection(list1, list2) == 2):
    print("yes, list 2 contains 2 elements of list 1")
else:
    print("no, list 2 does not contain 2 elements of list 1")

def my_func(list1, list2):
    count = 0
    for i in list1:
        for j in list2:
            if(i == j) : count += 1
    print(count)
    if(count >= 2) : return True
    else: return False


list1 = ["a", "b", "c"]
list2 = ["a", "f", "g", "b"]

if my_func(list1, list2):#list2 contains any 2 elements of list1:
    print("yes, list 2 contains 2 elements of list 1")
else:
    print("no, list 2 does not contain 2 elements of list 1")

J'utiliserais une description similaire à celle décrite dans la question suivante, mais cette fois vérifier la longueur de l'intersection des ensembles: Comment trouver l'intersection de liste?

list1 = ["a", "b", "c"]
list2 = ["a", "f", "g", "b"]

if len(list(set(a) & set(b))) == 2:
    print("yes, list 2 contains 2 elements of list 1")
else:
    print("no, list 2 does not contain 2 elements of list 1")

Vous pouvez utiliser itertools.combinations () pour obtenir tous les ensembles de deux éléments de list2 et voir s'ils sont des sous-ensembles de list1 :

import itertools

if any(set(comb).issubset(set(list1)) for comb in itertools.combinations(list2, 2)):
    print("yes, ...")
...

count = 0
for ele in list2:
    if ele in list1:
        count += 1
if count == 2:
    print ("yes, list 2 contains 2 elements of list 1")
else:
    print ("no, list 2 does not contain 2 elements of list 1")

list1 = ["a", "b", "c"]
list2 = ["a", "f", "g", "b"]

if len(set(list1).intersection(set(list2))) == 2:
    print("yes, list 2 contains 2 elements of list 1")
else:
    print("no, list 2 does not contain 2 elements of list 1")
The .intersection method takes two sets and finds what is common between them. If what is common between them is 2 elements, then you have what you want.

Cela fonctionne:

list1 = ["a", "b", "c"]
list2 = ["a", "f", "g", "b"]
val = 0
for idx in list1:
    for idx2 in list2:
        if idx == idx2:
            val += 1
if val == 2:
    print("yes, list 2 contains 2 elements of list 1")
else:
    print("no, list 2 does not contain 2 elements of list 1")