0
votes

Oracle - Min Valeur Regroupement par gamme d'enregistrements

Pour illustrer, supposons que j'ai les valeurs suivantes dans une table:

---------------------------------------
|    ID_USER    |     START_DATE      |
---------------------------------------
|       1       | 01/01/2018 08:00:00 |
|       2       | 01/01/2018 08:30:00 |
|       1       | 01/01/2018 08:45:00 |
|       2       | 01/01/2018 09:15:00 |
|       1       | 01/01/2018 09:45:00 |
---------------------------------------


1 commentaires

Vérifiez ce lien. je vais vous aider à résoudre ce problème.


3 Réponses :


1
votes

comparer la ligne actuelle et précédente à l'aide de Lag : xxx


0 commentaires

1
votes
with s (id_user, start_date) as (
select 1, to_date('01/01/2018 08:00:00', 'dd.mm.yyyy hh24:mi:ss') from dual union all
select 1, to_date('01/01/2018 08:15:00', 'dd.mm.yyyy hh24:mi:ss') from dual union all
select 2, to_date('01/01/2018 08:30:00', 'dd.mm.yyyy hh24:mi:ss') from dual union all
select 1, to_date('01/01/2018 08:45:00', 'dd.mm.yyyy hh24:mi:ss') from dual union all
select 1, to_date('01/01/2018 09:00:00', 'dd.mm.yyyy hh24:mi:ss') from dual union all
select 2, to_date('01/01/2018 09:15:00', 'dd.mm.yyyy hh24:mi:ss') from dual union all
select 2, to_date('01/01/2018 09:30:00', 'dd.mm.yyyy hh24:mi:ss') from dual union all
select 1, to_date('01/01/2018 09:45:00', 'dd.mm.yyyy hh24:mi:ss') from dual)
select id_user, start_date
from
   (select s.*, lag(id_user) over (order by start_date) prev_user
    from s
   )
where lnnvl(prev_user = id_user);

   ID_USER START_DATE
---------- -------------------
         1 2018-01-01 08:00:00
         2 2018-01-01 08:30:00
         1 2018-01-01 08:45:00
         2 2018-01-01 09:15:00
         1 2018-01-01 09:45:00

0 commentaires

0
votes
-- Oracle 12c+: Pattern matching
with s (id_user, start_date) as (
select 1, to_date('01/01/2018 08:00:00', 'dd.mm.yyyy hh24:mi:ss') from dual union all
select 1, to_date('01/01/2018 08:15:00', 'dd.mm.yyyy hh24:mi:ss') from dual union all
select 2, to_date('01/01/2018 08:30:00', 'dd.mm.yyyy hh24:mi:ss') from dual union all
select 1, to_date('01/01/2018 08:45:00', 'dd.mm.yyyy hh24:mi:ss') from dual union all
select 1, to_date('01/01/2018 09:00:00', 'dd.mm.yyyy hh24:mi:ss') from dual union all
select 2, to_date('01/01/2018 09:15:00', 'dd.mm.yyyy hh24:mi:ss') from dual union all
select 2, to_date('01/01/2018 09:30:00', 'dd.mm.yyyy hh24:mi:ss') from dual union all
select 1, to_date('01/01/2018 09:45:00', 'dd.mm.yyyy hh24:mi:ss') from dual)
select id_user, start_date
from s
match_recognize(
order by start_date
measures
   id_user    as id_user,
   start_date as start_date
pattern (v+)
define v as id_user = first(id_user)
);

   ID_USER START_DATE
---------- -------------------
         1 2018-01-01 08:15:00
         2 2018-01-01 08:30:00
         1 2018-01-01 09:00:00
         2 2018-01-01 09:30:00
         1 2018-01-01 09:45:00

0 commentaires