J'essaie d'inverser une chaîne sans affecter des caractères spéciaux, mais cela ne fonctionne pas. Voici mon code:
def reverse_each_word(str_smpl):
str_smpl = "String; 2be reversed..." #Input that want to reversed
lst = []
for word in str_smpl.split(' '):
letters = [c for c in word if c.isalpha()]
for c in word:
if c.isalpha():`enter code here`
lst.append(letters.pop())
continue
else:
lst.append(c)
lst.append(' ')
print("".join(lst))
return str_smpl
def main(): #This is called for assertion of output
str_smpl = "String; 2be reversed..." #Samplr input
assert reverse_each_word(str_smpl) == "gnirtS; eb2 desrever..." #output should be like this
return 0
4 Réponses :
Essayez le code suivant:
from string import punctuation
sp = set(punctuation)
str_smpl = "String; 2be reversed..." #Input that want to reversed
lst = []
for word in str_smpl.split(' '):
letters = [c for c in word if c not in sp]
for c in word:
if c not in sp:
lst.append(letters.pop())
continue
else:
lst.append(c)
lst.append(' ')
print("".join(lst))
ou essayez-le avec itheroTools.groupby ,
Voulez-vous dire comme ça ?:
def reverse_string(st):
rev_word=''
reverse_str=''
for l in st:
if l.isalpha():
rev_word=l+rev_word
else:
reverse_str+=rev_word
rev_word=''
reverse_str+=l
return reverse_str
def main():
string=' Hello, are you fine....'
print(reverse_string(string))
if __name__=='__main__':
main()
également nécessaire pour affirmer cela par la méthode principale ()
def reverse_string_without_affecting_number(text):
temp = []
text = list(text)
for i in text:
if not i.isnumeric():
temp.append(i)
reverse_temp = temp [::-1]
count = 0
for i in range(0,len(text)):
if not text[i].isnumeric():
text[i] = reverse_temp[count]
count +=1
else:
continue
return "".join(text)
print (reverse_string_without_affecting_number('abc1235de9f15ui'))